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Asked by anon-185717 to William, Rebecca, Martyna, Callum, Alice, Adam on 9 Nov 2018.
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William Glass answered on 9 Nov 2018:
Hmm, my best guess would be: If we think of the “sky” as the atmosphere then we’d need to find the pressure over a certain area (lets say 1 m^2) of the earth and then multiply this by the surface area of the earth using 4 * pi * r^2. Something along those lines. Of course we’d be ignoring several things that would change the value!
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Adam Berlie answered on 9 Nov 2018:
This is one of those abstract questions that makes you go “huh”? But it would be hard to say, like Callum I have no idea, but I’d be curious to know the answer!
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Rebecca Roddan answered on 11 Nov 2018: last edited 11 Nov 2018 2:50 pm
I think this would depend on how big you’d consider the sky to be. But a 1 m x 1m x 1m volume of air weights around 1.2 kg so if you worked out the volume of the sky it would be easy to work out the weight. The density of air (the mass per volume unit) decreases as you get further from earth, so this would also need to be considered.
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